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Polylinie mit neuer Google Maps API decodieren

Ich zeichne eine Route zwischen zwei Punkten in einer Karte. Ich erhalte die Punkte auf diese Weise:

StringBuilder urlString = new StringBuilder();
    urlString.append("http://maps.googleapis.com/maps/api/directions/json");
    urlString.append("?origin=");// from
    urlString.append(Double.toString(src.latitude));
    urlString.append(",");
    urlString.append(Double.toString(src.longitude));
    urlString.append("&destination=");// to
    urlString.append(Double.toString(dest.latitude));
    urlString.append(",");
    urlString.append(Double.toString(dest.longitude));
    urlString.append("&sensor=false&mode=");
    if (tipo != null) {
        urlString.append(tipo);
    }
return urlString.toString;

Ich erhalte die Antwort von Google und erhalte die JSON:

resp = new JSONObject(builder.toString());
                Log.i("Location", "Contenido del kml: "+resp);
                JSONArray routeObject = resp.getJSONArray("routes");
                JSONObject routes = routeObject.getJSONObject(0);
                JSONObject overviewPolylines = routes
                        .getJSONObject("overview_polyline");
                String encodedString = overviewPolylines.getString("points");
                ArrayList<LatLng> puntos=decodePoly(encodedString);

Die Antwort, die ich von Google bekomme: (im JSON-Format):

Response: {"status":"OK","routes":[{"waypoint_order":[],"summary":"R-3 and A-3","bounds":{"southwest":{"lng":-3.676540000000001,"lat":40.00040000000001},"northeast":{"lng":-2.99933,"lat":40.43357}},"legs":[{"duration":{"value":3267,"text":"54 mins"},"distance":{"value":85039,"text":"85.0 km"},"end_location":{"lng":-2.99933,"lat":40.00040000000001},"start_address":"Calle del General Díaz Porlier, 91, 28006 Madrid, Spain","end_address":"Camino Veinticuatro, 2, 16400 Tarancón, Cuenca, Spain","start_location":{"lng":-3.676540000000001,"lat":40.43331000000001},"via_waypoint":[],"steps":[{"html_instructions":"Head <b>north<\/b> on <b>Calle del Gral Díaz Porlier<\/b> toward <b>Calle de Maldonado<\/b>","duration":{"value":6,"text":"1 min"},"distance":{"value":29,"text":"29 m"},"end_location":{"lng":-3.676520000000001,"lat":40.43357},"polyline":{"points":"[email protected]"},"travel_mode":"DRIVING","start_location":{"lng":-3.676540000000001,"lat":40.43331000000001}},{"html_instructions":"Take the 1st <b>right<\/b> onto <b>Calle de Maldonado<\/b>","duration":{"value":62,"text":"1 min"},"distance":{"value":266,"text":"0.3 km"},"end_location":{"lng":-3.6734,"lat":40.43345},"polyline":{"points":"[email protected]@[email protected]"},"travel_mode":"DRIVING","start_location":{"lng":-3.676520000000001,"lat":40.43357}},{"html_instructions":"Take the 2nd <b>right<\/b> onto <b>Calle de Fco. Silvela<\/b>","duration":{"value":57,"text":"1 min"},"distance":{"value":245,"text":"0.2 km"},"end_location":{"lng":-3.671830000000001,"lat":40.4316},"polyline":{"points":"[email protected]@[email protected]]pBeBLK"},"travel_mode":"DRIVING","start_location":{"lng":-3.6734,"lat":40.43345}},{"html_instructions":"Slight <b>right<\/b> onto <b>Calle de Francisco Silvela<\/b>","duration":{"value":51,"text":"1 min"},"distance":{"value":437,"text":"0.4 km"},"end_location":{"lng":-3.66913,"lat":40.42827},"polyline":{"points":"oxwuF|clUJADAFCbBkAjAeA`BoA^[XUPMLMFEnAeALIdBuAZUPMXS"},"travel_mode":"DRIVING","start_location":{"lng":-3.671830000000001,"lat":40.4316}},{"html_instructions":"Turn <b>right<\/b> onto <b>Pl. de Manuel Becerra<\/b>","duration":{"value":32,"text":"1 min"},"distance":{"value":154,"text":"0.2 km"},"end_location":{"lng":-3.668380000000001,"lat":40.42827},"polyline":{"points":"ucwuF`[email protected][email protected]@@@@[email protected]@@[email protected]@[email protected]@[email protected]"},"travel_mode":"DRIVING","start_location":{"lng":-3.66913,"lat":40.42827}},{"html_instructions":"Turn <b>right<\/b> onto <b>Calle Alcala<\/b>","duration":{"value":61,"text":"1 min"},"distance":{"value":709,"text":"0.7 km"},"end_location":{"lng":-3.66107,"lat":40.43126000000001},"polyline":{"points":"[email protected]}[email protected]@[[email protected]@kB?KAQ]aAI[[email protected]@[email protected]"},"travel_mode":"DRIVING","start_location":{"lng":-3.668380000000001,"lat":40.42827}},{"html_instructions":"Turn <b>right<\/b> onto the ramp to <b>M-30\/A-3\/A-4<\/b>","duration":{"value":44,"text":"1 min"},"distance":{"value":453,"text":"0.5 km"},"end_location":{"lng":-3.660580000000001,"lat":40.42720000000001},"polyline":{"points":"kvwuFt`jU\\[email protected]?rCOvDY"},"travel_mode":"DRIVING","start_location":{"lng":-3.66107,"lat":40.43126000000001}},{"html_instructions":"Continue straight","duration":{"value":45,"text":"1 min"},"distance":{"value":1009,"text":"1.0 km"},"end_location":{"lng":-3.659120000000001,"lat":40.41822000000001},"polyline":{"points":"_}vuFr}[email protected]@[email protected]|[email protected]^[email protected]@[email protected]"},"travel_mode":"DRIVING","start_location":{"lng":-3.660580000000001,"lat":40.42720000000001}},{"html_instructions":"Take exit <b>7B<\/b> to merge onto <b>M-23<\/b> toward <b>Vicálvaro\/R-3\/Valencia<\/b>","duration":{"value":117,"text":"2 mins"},"distance":{"value":2552,"text":"2.6 km"},"end_location":{"lng":-3.63392,"lat":40.41499},"polyline":{"points":"{[email protected]^[email protected]@[email protected][email protected][email protected]@[email protected][email protected]@[email protected]@[email protected][email protected]{[email protected][@[email protected]@@G?A^{BjA}HF[[email protected]][email protected][email protected]@[email protected]@iGXmHDgFCgGG{DM

Und schließlich entschlüssle ich den erhaltenen String auf diese Weise, die ich hier in Stackoverflow in zahlreichen Antworten gefunden habe:

private ArrayList<LatLng> decodePoly(String encoded) {

    Log.i("Location", "String received: "+encoded);
    ArrayList<LatLng> poly = new ArrayList<LatLng>();
    int index = 0, len = encoded.length();
    int lat = 0, lng = 0;

    while (index < len) {
        int b, shift = 0, result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lat += dlat;

        shift = 0;
        result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lng += dlng;

        LatLng p = new LatLng((int) (((double) lat /1E5)* 1E6), (int) (((double) lng/1E5   * 1E6)));
        poly.add(p);
    }

   for(int i=0;i<poly.size();i++){
       Log.i("Location", "Point sent: Latitude: "+poly.get(i).latitude+" Longitude: "+poly.get(i).longitude);
   }
    return poly;
}

Ich denke, der Fehler liegt hier, weil ich ein für festgelegt habe, um die Punkte zu sehen, die dekodiert werden. Die Antwort lautet:

04-10 13:33:54.578: I/Location(25065): Point sent: Latitude: 90.0 Longitude: -110.0
04-10 13:33:54.578: I/Location(25065): Point sent: Latitude: 90.0 Longitude: -120.0
04-10 13:33:54.578: I/Location(25065): Point sent: Latitude: 90.0 Longitude: 100.0
04-10 13:33:54.578: I/Location(25065): Point sent: Latitude: 90.0 Longitude: 120.0
04-10 13:33:54.578: I/Location(25065): Point sent: Latitude: 90.0 Longitude: 40.0

Offensichtlich sind diese Punkte schlecht analysiert. Das Ergebnis ist, dass nirgendwo eine Linie gezeichnet wird. 

Meine Frage ist ... kann jemand die Antwort von Google parsen und in LatLng-Objekte (NICHT GeoPoints-Objekte) übersetzen?

Vielen Dank!

BEARBEITEN:

Dies ist der String, der gerade dekodiert wird:

04-10 13:50:51.608: I/Location(25065): String to decode: [email protected]}@[email protected]{[email protected]@[email protected]@[email protected]@[email protected]~ZwDtZuC`FKbCVjA`[email protected]@[email protected]][email protected]}DhC{PlBcM~GaY|DyS`BmPRy]yBu\UsNvAqObAuEnC}[email protected][}[email protected]}[email protected]`@~G}\|@aDdDoLn`@}[email protected]`JyV|[email protected]@{ZyBwVkBmOwB{^[email protected]@qYcCyS_DkPmAaK{@gRN{RbCkWrFgUbHmPxLsP|JwIpPwN|G}JfE}I|[email protected]]jCmXbHg\pIgSpGaLnN}P`JsHfVaNbQkHtZyIrOsCnTaCx\aA`[email protected]@nSRz]K`J{AxJiDfNkJjU{WbKkJpGeEpVkPpEiEzMcQjQw]nJyM~IoJ`IoKnH{NrOaWtIeJdNgNrLcPjKqOhIuI~MeJxKgErR{Cn]EjQkBjHqBfJeE|\yTlI_JvEqJxHsS|[email protected]~IeR|[email protected]@sNOoL_B}[email protected]]}N`CuO`D}GjHoHtFwC|[email protected]}BtHaF~D_FjLqSfGqE|[email protected]`BzNeAxQfAlJ{@jIwEjE}FvBuF|B{NtCsNrBgEdHiIdGuIxDoFpGkFhDaBrHyBbF[[email protected]{D|[email protected]@nE_F|Im`@tO_ZxCyEzJmKtHyElG_ClZeF|[email protected]|EuChGkHnK{[email protected][email protected]}[email protected]|BeGlEiYpD}[email protected]}[email protected]`ImMfMmXtFySpCkXRuN][email protected]}LxB{NvD{OjJaYbFsLnCcEtLoMfJyXzIiXbIiL~D_EzQcMjDeF|AcFhA_M`BkXpC_KjCsDnDeClQcHvEgElFqJfF_Jp\[email protected]]`WkWlVy`@nOcTz`@[email protected]_ZbNkQ~Tu^jJaUhCuIpHgUrPi\[email protected]@~McQh\e]vTaU~KcF~KoGhG{KzF{HzGmDbDwBfDiEzB}[email protected]@[email protected]@tDgC`ZeJnXkHrKmB~EeB~C{A`[email protected]@yEhDeOrCuQ|A}EvAwFdDgAfGSrHUJ\[email protected]@_A|[email protected]|C}[email protected]~Ds][email protected][email protected]

Wenn Sie mit LatLng formatate die Art der Erstellung der LatLng-Objekte meinen, können Sie die decodePoly-Methode sehen. Diese latLng-Objekte werden den PolylineOptions-Objekten hinzugefügt, und diese werden der Karte auf folgende Weise hinzugefügt:

PolylineOption ruta=new PolylineOptions();
for(int i=0;i<puntos.size();i++){
ruta.add(new LatLng(puntos.get(i).latitude, puntos.get(i).longitude));                      
}//puntos is an array where the array returned by the decodePoly method are stored                  
ruta.color(Color.RED).width(7);                     
Polyline polygon=mapa.addPolyline(ruta);
21
Fustigador

Ich habe das decodePoly geändert, das ich für dieses verwendet habe, das ich nach langer Suche in Google gefunden habe, und jetzt ist die Route ordnungsgemäß gezeichnet. 

http://wptrafficanalyzer.in/blog/route-zwischen-zwei-standorte-mit-wegpunkten-in-google-map-Android-api-v2/

Ändern 

LatLng p = new LatLng((int) (((double) lat /1E5)* 1E6), (int) (((double) lng/1E5   * 1E6)));

zum 

LatLng p = new LatLng((((double) lat / 1E5)),(((double) lng / 1E5)));

Und jetzt funktioniert es.

27
Fustigador

Für diejenigen, die dies jetzt brauchen, gibt es eine Open-Source-Bibliothek mit vielen nützlichen Informationen zur Google Maps-Android-API, einschließlich Dekodierung und Kodierung von Polylinien.

Check it out unter Android Maps Utils und Android Maps Util Github . Zum Dekodieren und Kodieren verwenden:

PolyUtil.decode(String encodedPath);
PolyUtil.encode(List<LatLng> path);
9
CounterFlame

Gleiches in Javascript

    function decodePolyline(encoded) {
        if (!encoded) {
            return [];
        }
        var poly = [];
        var index = 0, len = encoded.length;
        var lat = 0, lng = 0;

        while (index < len) {
            var b, shift = 0, result = 0;

            do {
                b = encoded.charCodeAt(index++) - 63;
                result = result | ((b & 0x1f) << shift);
                shift += 5;
            } while (b >= 0x20);

            var dlat = (result & 1) != 0 ? ~(result >> 1) : (result >> 1);
            lat += dlat;

            shift = 0;
            result = 0;

            do {
                b = encoded.charCodeAt(index++) - 63;
                result = result | ((b & 0x1f) << shift);
                shift += 5;
            } while (b >= 0x20);

            var dlng = (result & 1) != 0 ? ~(result >> 1) : (result >> 1);
            lng += dlng;

            var p = {
                latitude: lat / 1e5,
                longitude: lng / 1e5,
            };
            poly.Push(p);
        }
        return poly;
    }
5
L. Zampetti

Diese Methode eignet sich zum Dekodieren der Polylinie

 private List<LatLng> decodePoly(String encoded) {
    List<LatLng> poly = new ArrayList<>();
    int index = 0, len = encoded.length();
    int lat = 0, lng = 0;

    while (index < len) {
        int b, shift = 0, result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lat += dlat;

        shift = 0;
        result = 0;
        do {
            b = encoded.charAt(index++) - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lng += dlng;

        LatLng p = new LatLng((((double) lat / 1E5)),
                (((double) lng / 1E5)));
        poly.add(p);
    }

    return poly;
}

So bekomme ich Polylinie

JSONObject poly = route.getJSONObject("overview_polyline");
String polyline = poly.getString("points");
polyLineList = decodePoly(polyline);
1
AMAN SINGH

Gleiches in Pascal (Delphi):

    var lat,lon,lat_f,lon_f:Double;
    var index:Integer;
    var len:Integer;
    var b:Integer;
    var shift:Integer;
    var result:Integer;
    var encoded:String;
    var dlat:Integer;
    var dlng:Integer;

  encoded:='ibgqGq}ycIMvM';
  len:= Length(encoded);

    lat:=0;
    lon:=0;
  While (index <=len) do
    begin
    b:=$20;
    shift:=0;
    result:=0;
    While (b >= $20) do
      begin
      b:=ord(encoded[index]);
      b:=b-63;
      index:= index+1;
      result:= result OR (b AND $1f) Shl shift;
      shift:=shift + 5;
      end;

      If (result And 1) <> 0 Then
        dlat:= Not (result Shr 1)
      Else
        dlat:= result Shr 1;
      lat:=lat+dlat;

      shift:= 0;
      result:= 0;
      b:=$20;
      While (b >= $20) do
        begin
      b:=ord(encoded[index]);
      b:=b-63;
        index:= index+1;
        result:= result OR (b AND $1f) Shl shift;
        shift:=shift + 5;
        end;

        If (result And 1) <> 0 Then
            dlng:= Not (result Shr 1)
        Else
            dlng:= result Shr 1;
        lon:=lon+dlng;
{ The coordinates of the point are used for our purposes }
        lon_f:=lon/100000.0;
        lat_f:=lat/100000.0;
    end; //while
0
Alexey Ivakhin

Hier ist die Implementierung in iOS für alle, die neugierig sind. Diese basiert vollständig auf der Antwort von @ Fustigador, wurde aber in iOS konvertiert. Beachten Sie, dass ich den Code nicht entsprechend formatiert habe. Ich habe nur einige Variablen hinzugefügt, um das versprochene Objekt zurückzugeben.

- (GMSPath *)decodedPolylinePathFromEncodedPolylineString:(NSString *)encodedPolylineString {


    NSString *decodedPolylineString = @"";
    GMSMutablePath *decodedPolylinePath = [GMSMutablePath new];
    CLLocationCoordinate2D decodedCoordinate;
    CLLocationDegrees latitude, longitude;

    int index = 0;
    NSUInteger len = encodedPolylineString.length;

    int lat = 0, lng = 0;

    while (index < len) {
        int b, shift = 0, result = 0;
        do {

            b = [encodedPolylineString characterAtIndex:index++] - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lat += dlat;

        shift = 0;
        result = 0;
        do {
            b = [encodedPolylineString characterAtIndex:index++] - 63;
            result |= (b & 0x1f) << shift;
            shift += 5;
        } while (b >= 0x20);
        int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
        lng += dlng;

        latitude =  (((double) lat / 1E5));
        longitude = (((double) lng / 1E5));

        decodedCoordinate = CLLocationCoordinate2DMake(latitude, longitude);

        decodedPolylineString = [NSString stringWithFormat:@"%f%f", latitude, longitude];
        ;
        NSLog(@"%@",decodedPolylineString);

        [decodedPolylinePath addCoordinate:decodedCoordinate];
    }


    return decodedPolylinePath;
}
0
BigSauce